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0=6x^2+x-245
We move all terms to the left:
0-(6x^2+x-245)=0
We add all the numbers together, and all the variables
-(6x^2+x-245)=0
We get rid of parentheses
-6x^2-x+245=0
We add all the numbers together, and all the variables
-6x^2-1x+245=0
a = -6; b = -1; c = +245;
Δ = b2-4ac
Δ = -12-4·(-6)·245
Δ = 5881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{5881}}{2*-6}=\frac{1-\sqrt{5881}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{5881}}{2*-6}=\frac{1+\sqrt{5881}}{-12} $
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